Contoh Pengiraan Dalam Networking
Dori Dorian
Soalan-soalan :

1) 192 . 168 . 1 . 12/29
29 = 1111 1000
i) Bilangan Host = 2^3 ii) Bilangan network = 2^5
= 8 - 2 = 32
= 6
 iii) Subnet mask = 1111 1000
= 128 + 64 + 32 + 16 + 8
= 248
 iv) Network Address = 192 . 168 . 1 . 8
Broadcast Address = 192 . 168 . 1 . 15

2) 192 . 168 . 1 . 250/26
 26 = 1100 0000
i) Cari bilangan host = 2^6 ii) Cari bilangan network = 2^2
= 64 - 2 = 4
= 62 iii) Subnet mask = 1100 0000
= 128 + 64
= 192 iv) Network Address = 192 . 168 . 1 . 192
Broadcast Address = 192 . 168 . 1 . 255

3) 192 . 168 . 1 . 87/27
27 = 1110 0000
 i) Cari bilangan host = 2^5 ii) Cari bilangan network = 2^3
= 32 - 2 = 8
= 30 iii) Cari subnet mask = 1110 0000
= 128 + 64 + 32
= 224 iv) Network Address = 192 . 168 . 1 . 64
Broadcast Address = 192 . 168 . 1 . 95
 
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