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Cara mengira guna rumus anding
Rumus Anding

0 -- 0 = 0
1 -- 1 = 1
0 -- 1 = 0
1 -- 0 = 0

Contoh :
1) Diberi nombor-nombor yang berikut :
192 . 168 . 1 . 64
255 . 255 . 255 . 192
Penyelesaiannya : -

Langkah 1 :
192 . 168 . 1 . 64 (Tukar ke dalam bentuk binary spt dibawah)
1100 0000 . 1010 1000 . 0000 0001 . 0100 0000

255 . 255 . 255 . 192
(Tukar ke dalam bentuk binary spt dibawah)
1111 1111 . 1111 1111 . 1111 1111 . 1100 0000

Langkah 2 :
Tambahkan kedua-dua nombor yang sudah ditukar kepada binary tadi..

1100 0000 1010 1000 0000 0001 0100 0000
11 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 +
-------------------------------------------------------------------
1100 0000 1010 1000 0000 0001 0100 0000
-------------------------------------------------------------------

Langkah 3 :

Tukar jawapan yang ditambah tadi kepada decimal :
1100 0000 . 1010 1000 . 0000 0001 . 0100 0000 (Jawapan tadi)
192 . 168 . 1 . 64

Jawapannya : 192 . 168 . 1 . 64
Contoh Pengiraan Dalam Networking
Soalan-soalan :

1) 192 . 168 . 1 . 12/29
29 = 1111 1000
i) Bilangan Host = 2^3 ii) Bilangan network = 2^5
= 8 - 2 = 32

= 6
iii) Subnet mask = 1111 1000
= 128 + 64 + 32 + 16 + 8
= 248

iv) Network Address = 192 . 168 . 1 . 8
Broadcast Address = 192 . 168 . 1 . 15


2) 192 . 168 . 1 . 250/26
26 = 1100 0000
i) Cari bilangan host = 2^6 ii) Cari bilangan network = 2^2
= 64 - 2 = 4

= 62
iii) Subnet mask = 1100 0000
= 128 + 64

= 192
iv) Network Address = 192 . 168 . 1 . 192
Broadcast Address = 192 . 168 . 1 . 255


3) 192 . 168 . 1 . 87/27
27 = 1110 0000
i) Cari bilangan host = 2^5 ii) Cari bilangan network = 2^3
= 32 - 2 = 8

= 30
iii) Cari subnet mask = 1110 0000
= 128 + 64 + 32

= 224
iv) Network Address = 192 . 168 . 1 . 64
Broadcast Address = 192 . 168 . 1 . 95
 
Valid / Invalid And specify their class 1)
1) 126 . 100 . 1 . 1 = Valid (Class A)

2) 192 . 168 . 254 . 0 = Invalid (Class C)

3) 204 . 204 . 7 . 0 = Invalid (Class C)

4) 201 . 100 . 11 . 5 = Valid (Class C)

5) 192 . 5 . 5 . 5 = Valid (Class C)

6) 205 . 7 . 256 . 11 = Invalid (Class C)

7) 300 . 10 . 100 . 13 = Invalid

8) 0 . 1 . 2 . 3 = Invalid

9) 255 . 223 . 100 . 101 = Invalid (Class E)

10) 253 . 252 . 254 . 255 = Invalid
(Class E)


11) 1 . 1 . 1 . 1 = Valid
(Class A)

12) 160 . 1 . 1 . 258 = Invalid (
Class B)
Cara mengira bilangan host dan network
1) 10 . 0 . 0 . 0 / 15
Class A = 255 . 0 . 0 . 0
i) Bilangan Host = 255 . 0 . 0 . 0
1111 1111 . 1111 1110 . 0000 0000 . 0000 0000
= 2^17
= 131072 - 2

= 131070
ii) Bilangan Network = 2^7
= 128

2) 128 . 3 . 0 . 0 / 30
30 = 1111 1100
i) Bilangan Host = 2^2 ii) Bilangan Network = 2^6
= 4 - 2
= 64
= 2


3) 192 . 168 . 1 . 0 / 27
27 = 1110 0000
i) Bilangan Host = 2^5 ii) Bilangan Network = 2^3
= 32 - 2
= 8
= 30


4) 11 . 0 . 0 . 0 / 12
Class A = 255 . 0 . 0 . 0
i) Bilangan Host = 2^20 ii) Bilangan Network = 2^4
= 1048576 - 2 = 16
= 1048574
5) 13 . 0 . 0 . 0 / 30
i) Bilangan Host = 2^2 ii) Bilangan Network = 2^6
= 4 - 2 = 64
= 2


6) 130 . 11 . 0 . 0 / 22 Class B = 255 . 255 . 0 . 0
i) Bilangan Host = 2^10 ii) Bilangan Network = 2^6
= 1024 - 2 = 64
= 1022


7) 132 . 9 . 0 . 0 / 18
Class B = 255 . 255 . 0 . 0
i) Bilangan Host = 2^14 ii) Bilangan Network = 2^2
= 16384 - 2 = 4
= 16382


8) 6 . 0 . 0 . 0 / 9
Class A = 255 . 0 . 0 . 0
i) Bilangan Host = 2^23 ii) Bilangan Network = 2^1
= 8388608 - 2 = 2
=
8388606
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